OK...glad you are all here to help.
8 of item a
16 of item b
4 of item c
How many combinations can I make? It takes all 3 together to make 1.
Ok...starting to get the feel of the dialogue here.
Keep in mind I am a marketing guy...calculating margins is about as heavy as I get into math.
If there are
8 different versions of a
16 different versions of b
and 4 different versions of c
how many unique items can be put together?
There are 8 different types of a's; 16 different types of b's; and 4 different types of c's.
So to have one of each a, b, & c, we can choose the a in 8 ways, the b in 16 ways, and the c in 4 ways. That is 512 ways to make up a package of one a, one b, and one c. But each package is different because the types are themselves different.