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Math Help - Combination Calculation

  1. #1
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    Combination Calculation

    OK...glad you are all here to help.

    8 of item a
    16 of item b
    4 of item c

    How many combinations can I make? It takes all 3 together to make 1.
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  2. #2
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    Please post the question exactly as it is written.
    What you have posted is meaningless.
    Always give the exact wording.
    It is a waste of time to guess at meaning only to be wrong.
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  3. #3
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    there is no question...

    the item contains 1 of each of a, b, and c.
    there are 8 versions of a
    16 versions of b
    and 4 versions of c

    How many items are possible?

    Thanks for your polite and prompt response.
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  4. #4
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    Quote Originally Posted by cjbmxr View Post
    the item contains 1 of each of a, b, and c.
    there are 8 versions of a
    16 versions of b
    and 4 versions of c
    How many items are possible?
    Written this way the answer is simply: (8)(16)(4)=512
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  5. #5
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    Ok...starting to get the feel of the dialogue here.

    Keep in mind I am a marketing guy...calculating margins is about as heavy as I get into math.

    If there are
    8 different versions of a
    16 different versions of b
    and 4 different versions of c

    how many unique items can be put together?
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  6. #6
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    Quote Originally Posted by cjbmxr View Post
    Keep in mind I am a marketing guy...calculating margins is about as heavy as I get into math.
    If there are
    8 different versions of a
    16 different versions of b
    and 4 different versions of c
    how many unique items can be put together?
    There are 8 different types of a's; 16 different types of b's; and 4 different types of c's.
    So to have one of each a, b, & c, we can choose the a in 8 ways, the b in 16 ways, and the c in 4 ways. That is 512 ways to make up a package of one a, one b, and one c. But each package is different because the types are themselves different.
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