1. ## Combination Calculation

OK...glad you are all here to help.

8 of item a
16 of item b
4 of item c

How many combinations can I make? It takes all 3 together to make 1.

2. Please post the question exactly as it is written.
What you have posted is meaningless.
Always give the exact wording.
It is a waste of time to guess at meaning only to be wrong.

3. ## there is no question...

the item contains 1 of each of a, b, and c.
there are 8 versions of a
16 versions of b
and 4 versions of c

How many items are possible?

Thanks for your polite and prompt response.

4. Originally Posted by cjbmxr
the item contains 1 of each of a, b, and c.
there are 8 versions of a
16 versions of b
and 4 versions of c
How many items are possible?
Written this way the answer is simply: $(8)(16)(4)=512$

5. Ok...starting to get the feel of the dialogue here.

Keep in mind I am a marketing guy...calculating margins is about as heavy as I get into math.

If there are
8 different versions of a
16 different versions of b
and 4 different versions of c

how many unique items can be put together?

6. Originally Posted by cjbmxr
Keep in mind I am a marketing guy...calculating margins is about as heavy as I get into math.
If there are
8 different versions of a
16 different versions of b
and 4 different versions of c
how many unique items can be put together?
There are 8 different types of a's; 16 different types of b's; and 4 different types of c's.
So to have one of each a, b, & c, we can choose the a in 8 ways, the b in 16 ways, and the c in 4 ways. That is 512 ways to make up a package of one a, one b, and one c. But each package is different because the types are themselves different.