I have 4 assignments to pass to three different people to do for me. What is the probability that each person will receive at least one assignment?
Total combination: = = 15
P(each person receive at least one assignment) = =
My answer is 0.2
but it's wrong
It's a MCQ question with options: (A) , (B) , (C) , (D) , (E)
Thanks for the reply.
Ya if the assignments are distinct, there will be a total of possibilities.
But how do you find the 36?
My interpretation will be to permute 4 assignments among the 3 people (since each of them will receive one assignment), which is 4. 3. 2. 3 = 72, since the last assignment could be allocated to any one among the three. Therefore answer is A?