A shipment of 10 items has two defective and eight nondefective items. In the inspection of the shipment, a sample of items will be selected and tested. If a defective item is found, the shipment of 10 items will be rejected.

If a sample of 3 items is selected, what is the probability that the shipment will be rejected?

I used f(x)=(nCr(2,x)*nCr(8,3-x))/nCr(10,3)

f(1)=.466667

Book answer is .5333333.

Is the book right?