A dice has 6 faces numbered 1-6. If I roll it 9 times what is the probability that I will get the number 4 exactly 6 times? Answer as a decimal accurate to at least 4 significant figures.
The singular of dice is a die. So a die is rolled nine times.
The probability of getting a 4 on any roll is $\displaystyle \frac {1}{6}$.
In nine rolls there are $\displaystyle 9 \choose 6$ ways to get exactly six 4’s in six.
$\displaystyle {9 \choose 6}\left( {\frac{1}{6}} \right)^6 \left( {\frac{5}{6}} \right)^3 $