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Math Help - permutation/ probability question part-2

  1. #1
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    permutation/ probability question part-2

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    Answer is 120.
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    how? i hardly care abt d answer as long as i understand d way .. no doing it for marks in a test or anything..
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    Quote Originally Posted by champrock View Post
    how? i hardly care abt d answer as long as i understand d way .. no doing it for marks in a test or anything..
    That answer is correct: {10 \choose 3} =120
    Any set of three integers can be arranged is assending order.
    You have 10 of them.
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    "any set of integers".

    d questions says N1 < N2 < N3 whcih means the number from the first box should be the smallest followed by the number frm the second and the largest number from the third.
    so 3<6<7 is a valid combination but 8<5<9 is not because the number in the first box is greater than the second.
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    Quote Originally Posted by champrock View Post
    "any set of integers". d questions says N1 < N2 < N3 whcih means the number from the first box should be the smallest followed by the number frm the second and the largest number from the third.
    so 3<6<7 is a valid combination but 8<5<9 is not because the number in the first box is greater than the second.
    My answer is correct. The reason given is also correct.
    This is a well known problem.
    So you just think about for awhile. After all you have been the same answer twice.
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