# Thread: permutation/ probability question part-2

1. ## permutation/ probability question part-2

3. how? i hardly care abt d answer as long as i understand d way .. no doing it for marks in a test or anything..

4. Originally Posted by champrock
how? i hardly care abt d answer as long as i understand d way .. no doing it for marks in a test or anything..
That answer is correct: ${10 \choose 3} =120$
Any set of three integers can be arranged is assending order.
You have 10 of them.

5. "any set of integers".

d questions says N1 < N2 < N3 whcih means the number from the first box should be the smallest followed by the number frm the second and the largest number from the third.
so 3<6<7 is a valid combination but 8<5<9 is not because the number in the first box is greater than the second.

6. Originally Posted by champrock
"any set of integers". d questions says N1 < N2 < N3 whcih means the number from the first box should be the smallest followed by the number frm the second and the largest number from the third.
so 3<6<7 is a valid combination but 8<5<9 is not because the number in the first box is greater than the second.
My answer is correct. The reason given is also correct.
This is a well known problem.
So you just think about for awhile. After all you have been the same answer twice.