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Solve for n if nP5 = 120 x nC3

Quote: Originally Posted by mathamatics112 Solve for n if nP5 = 120 x nC3 (eq1) (eq2) eq1 = eq2 n(n-1)(n-2) will cancel: solve to get n = 8 or n = -1. However since n must be greater than 0 only n = 8 is a solution