Solve for n if nP5 = 120 x nC3
Originally Posted by mathamatics112 Solve for n if nP5 = 120 x nC3 (eq1) (eq2)
eq1 = eq2
n(n-1)(n-2) will cancel:
solve to get n = 8 or n = -1.
However since n must be greater than 0 only n = 8 is a solution