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Math Help - Urgent help for statistics please!

  1. #1
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    Urgent help for statistics please!

    30% of chicken is contaminated, if a person buys 12, what's the possibility that 6 of them are contaminated? thanks
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  2. #2
    MHF Contributor
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    Hi

    Let X be the random variable which counts the number of chickens contaminated out of 12.

    X follows a binomial distribution (with parameters n=12 and p=0.30) because it is the number of "yes" in a sequence of 12 independent yes/no experiments (contaminated / not contaminated).

    P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}

    Therefore P(X=6) = \binom{12}{6} 0.30^6\: (1-0.30)^{12-6}

    P(X=6) = \binom{12}{6} 0.30^6 \: 0.70^6
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  3. #3
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    I don't get this

    How do you solve (12 over 6)? how do you put that in the equation?


    Quote Originally Posted by running-gag View Post
    Hi

    Let X be the random variable which counts the number of chickens contaminated out of 12.

    X follows a binomial distribution (with parameters n=12 and p=0.30) because it is the number of "yes" in a sequence of 12 independent yes/no experiments (contaminated / not contaminated).

    P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}

    Therefore P(X=6) = \binom{12}{6} 0.30^6\: (1-0.30)^{12-6}

    P(X=6) = \binom{12}{6} 0.30^6 \: 0.70^6
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  4. #4
    MHF Contributor
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    Quote Originally Posted by Kalyn View Post
    How do you solve (12 over 6)? how do you put that in the equation?
    \binom{12}{6} is the binomial coefficient

    12-6)!}" alt="\binom{12}{6} = \frac{12!}{6! \12-6)!}" />
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