The computations in this problem on a recent Praxis II exam appear simple however I am not completely sure what they are asking for.

A method of estimation temperature Fahrenheit is to double the Celsius temperature and add 30°.

Estimated = 2C + 30

Actual = 1.8C + 32

On two separate days you are given the temperature Celsius. What is themaximum errorallowedin the estimation of the Fahrenheit temperature versus the actual Fahrenheit temperature?

Day 1 -20

Est 2(-20) + 30 = -10

Act 1.8(-20) + 32 = -4

Variance = 6

Day 2 30

Est 2(30) + 30 = 90

Act 1.8(30) + 32 = 86

Variance = 4

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