Let C=cereal T=Toast N=No breakfast
P(C) = 0.85 P(T) = 0.60 P(CnT)=0.5
=> P(CuT) = P(C) + P(T) - P(CnT)
= 0.85 + 0.60 - 0.5
therefore neither is:
P(N)=1-0.95 = 0.05
The question goes...
If 85% of people have a bowl of cereal for breakfast, 60% of people have some toas for breakfast, and 50% of people have both cereal and toast for breakfast, what proportion of people have neither cereal nor toast for breakfast?
I know it's simple, but I can't remember how to do it can anyone help?
My preliminary guess (educated, obviously) was 27.5%...