In Lotto 6-53, there is a box with 53 balls, numbered 1 to 53. Six balls are drawn at random without replacement from the box. You win the grand prize if your lottery numbers are the same as the numbers on the six balls; order does not matter.
Person A bought two tickets:
#1: 5 12 21 30 42 51
#2: 7 11 25 30 42 49
Person B bough two tickets:
#1: 7 11 25 28 34 50
#2: 9 14 20 22 37 45
Which person has a better chance of winning? Or are their chances the same? Explain briefly.
I guess my issue is with this that I'm not sure how to approach the question. Clearly the ball draws are independent and any given number has the same chance of being pulled. So my first thought is that they have the same chances.
That's how I feel too. Each ticket has the same chance of winning regardless of common numbers on them.
But "one has 2 tickets with all the same numbers on them" is a different story.
-O not always sure.
you need that your 6 numbers, or in other words, your combination of 6 numbers, will be the exact combination of the machine. start with asking yourself how many possible combinations of 6 numbers are there in a group of 53 numbers.
In such lotteries the balls are (meant to be) always drawn in such a way that each combination is equally likely .....
Originally Posted by Requiems
This suggestion is not relevant to answering the question.
Originally Posted by WeeG