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Math Help - Seemingly simple probability question...

  1. #1
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    Question Seemingly simple probability question...

    This looks to be pretty straight forward, but I am not getting the right answer...
    300 chickens are in a barn. 63 are brown roosters and 77 are black roosters. 64 are brown hens and 96 are black hens. So, there are a total of 140 roosters and 160 hens, also there are 127 brown chickens and 173 black chickens. If one is chosen at random, what is the probability that it is a brown hen.
    When I worked this through, I took (64/160)( 160/300) and came up with .213333333333...
    Am I on the right track here?
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  2. #2
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    Hello,
    Quote Originally Posted by bemidjibasser View Post
    This looks to be pretty straight forward, but I am not getting the right answer...
    300 chickens are in a barn. 63 are brown roosters and 77 are black roosters. 64 are brown hens and 96 are black hens. So, there are a total of 140 roosters and 160 hens, also there are 127 brown chickens and 173 black chickens. If one is chosen at random, what is the probability that it is a brown hen.
    When I worked this through, I took (64/160)( 160/300) and came up with .213333333333...
    Am I on the right track here?
    There are 64 brown hens for a total of 300 chickens.
    So the probability is 64/300
    Why complicating things by writing (64/160)(160/300) ? (which gives the correct result, but obviously shows that the reasoning was not the correct one )
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