# Seemingly simple probability question...

• Feb 23rd 2009, 10:58 AM
bemidjibasser
Seemingly simple probability question...
This looks to be pretty straight forward, but I am not getting the right answer...
300 chickens are in a barn. 63 are brown roosters and 77 are black roosters. 64 are brown hens and 96 are black hens. So, there are a total of 140 roosters and 160 hens, also there are 127 brown chickens and 173 black chickens. If one is chosen at random, what is the probability that it is a brown hen.
When I worked this through, I took (64/160)( 160/300) and came up with .213333333333...
Am I on the right track here?
• Feb 23rd 2009, 11:05 AM
Moo
Hello,
Quote:

Originally Posted by bemidjibasser
This looks to be pretty straight forward, but I am not getting the right answer...
300 chickens are in a barn. 63 are brown roosters and 77 are black roosters. 64 are brown hens and 96 are black hens. So, there are a total of 140 roosters and 160 hens, also there are 127 brown chickens and 173 black chickens. If one is chosen at random, what is the probability that it is a brown hen.
When I worked this through, I took (64/160)( 160/300) and came up with .213333333333...
Am I on the right track here?

There are 64 brown hens for a total of 300 chickens.
So the probability is 64/300
Why complicating things by writing (64/160)(160/300) ? (which gives the correct result, but obviously shows that the reasoning was not the correct one (Worried))