Hello, zerobladex!

IthinkI've reasoned correctly.

If I'm wrong,surelysomeone will point it out.

There are 13 guests at a hotel. You are one of the guests.

There are 3 rooms: one with 2 beds, one with 3 beds, and one with 4 beds.

If nine guests are chosen at random and placed randomly into the rooms,

what is the probability that you will be chosen and will be in the room with 2 beds?

There are: . ways the 9 guests can be chosen.

. . There are: . ways that you are among the nine.

. . Hence: .

There are: . ways to assign the rooms.

. . There are: . ways that you are given the 2-bed room.

. . Hence: .

Therefore: .