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Math Help - Permutations

  1. #1
    Junior Member
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    Permutations

    Hi

    Find the number of ways of arranging 6 women and 3 men to stand in a row so that all 3 men are standing together.

    The book says 7!x3!, but I think this answer should be multiplied by 2, for the men being in front or behind.

    Any help would be great.

    Thanks.
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  2. #2
    MHF Contributor
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    Quote Originally Posted by woollybull View Post
    Hi

    Find the number of ways of arranging 6 women and 3 men to stand in a row so that all 3 men are standing together.

    The book says 7!x3!, but I think this answer should be multiplied by 2, for the men being in front or behind.

    Any help would be great.

    Thanks.

    The book is right .

    MMM(1!)WWWWWW(6!) =7!

    The men's position can be changed (which is what you meant by in front and behind ) so there will be another 3!
    =7!x3!
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  3. #3
    Junior Member
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    For some reason after reading the question I thought that the men and women had to be together, like 3!7! + 7!3!.
    Thanks for your help.
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