# Statistic help

• Feb 2nd 2009, 05:12 PM
Statistic help
The situation is :

suppose the annual consumption of chicken mean is 20.84 pounds per person, and that the standard deviation for the consumption of chicken per person is 9.193 pounds. The mean weight of chicken consumed for a sample of 200 randomly selected people is one value of many that form the sampling distribution of sample means

What is the mean value for the sampling distribution and what is the standard deviation?

Thank you whoever tackles this one
• Feb 3rd 2009, 04:02 AM
mr fantastic
Quote:

Substitute $\mu = 20.84$, $\sigma = 9.193$ and $n = 200$ into the well known formulae for $\mu_{\overline{X}}$ and $\sigma_{\overline{X}}$ (see here: Sampling distribution - Wikipedia, the free encyclopedia).