All faces of the die are equally likely. The favourable outcomes in this case are:

1, 3, 5

out of a total of 6 possible outcomes. Therefore the probability of an odd

number when the die is rolled is:

[number of favourable outcomes]/[total number of outcomes] = 3/6 = 0.5

Here the favourable outcomes are A , 2 , 3 .., 10, J, Q, K of diamonds andb) A card is drawn from a well-shuffled deck of 52 cards. Find the probability that the card is either a 10 or a diamond.

10 of hearts, 10 of Spades, 10 of clubs which is a total of 16 favourable cases.

Total number of outcomes = 52, so the required probability is: 16/52=4/13

RonL