I have absolutely no idea how bridge works, although I don't think it really applies to this problem...but anyway.
a) what is the probability that your bridge partner has exactly two aces, given that she has at least one ace?
b) what is the probability that your bridge partner has exactly two aces, given that she has the ace of spades?
I know that Pr(2 aces given >= 1 ace) = P(2A and >= 1A)/P(>=1A), but I don't know what these values are. What would be the probability of having at least 1 ace? I'm not sure how the cards are dealt and/or how many are held at a time
is the number of combinations of 48 objects taken 13 at a time (also know as a "binomial coefficient").
The probability of having no aces is
There are possible hands, each of which is equally likely. If you have exactly 2 aces then there are ways to pick the aces and ways to pick the remaining 11 cards, so the probability isHow would I find the probability of having exactly 2?