# Help with a Probability problem!

• Jan 27th 2009, 05:53 PM
glue'd'n'math
Help with a Probability problem!

What is the probability that when 2 numbered cubes are thrown that
at least 1 will land with the number 6 up?

Thank you very much, for response!
• Jan 27th 2009, 06:47 PM
Shyam
Quote:

Originally Posted by glue'd'n'math

What is the probability that when 2 numbered cubes are thrown that
at least 1 will land with the number 6 up?

Thank you very much, for response!

The total number of outcomes, when 2 cubes are thrown, are (6)(6) = 36

Number of favorable outcomes are

(1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5)

so, 11 outcomes.

So, Probability $= \frac{11}{36}$
• Jan 27th 2009, 07:28 PM
TKHunny
"Numbered Cubes"? What a silly question. What are the numbers on the cubes?

1, 3, 5, 7, 9, 11? Pr(at least one 6) = 0.00

6, 6, 6, 6, 6, 6? Pr(at least one 6) = 1.00

I think this is an example of PC Mathematics. Will the use of the word "dice" hurt someones feelings? Oh, no!!! They are teaching my son gambling in school!!

"Dice" are understood to be cubes with the numbers 1, 2, 3, 4, 5, and 6 on the sides. "Numbered Cubes" are not understood to be anything unless it is defined. Maybe "Numbered Cubes" are understood to be "Dice"?

I would argue this question if it showed up on my kid's homework.
• Jan 28th 2009, 11:59 AM
glue'd'n'math
Thank you very much for your response!
I got that one. Thank you

glue'd'n'math(Happy)