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Math Help - pleas help. probability.

  1. #1
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    pleas help. probability.

    How many diff. 3-member comittees can be chosen if the committee cannot have all females or all males?

    35 members (15 females & 20 males)
    3 member committee: President, VP, Treasurer

    back of the book says 29,700.
    but i keep getting different answers.

    Can anyone please show me HOW to get that answer?

    thank you in advance
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  2. #2
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    Quote Originally Posted by Big-K View Post
    How many diff. 3-member comittees can be chosen if the committee cannot have all females or all males?

    35 members (15 females & 20 males)
    3 member committee: President, VP, Treasurer

    back of the book says 29,700.
    but i keep getting different answers.

    Can anyone please show me HOW to get that answer?

    thank you in advance
    In the committe you can have either 1 female and 2 males or 2 females and 1 male:

     {15 \choose 1} \cdot {20 \choose 2} + {15 \choose 2} \cdot {20 \choose 1} = \, ....

    Then you have to multiply by 3! = 6 (why?)
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