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Math Help - Prob. Question

  1. #1
    Member classicstrings's Avatar
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    Prob. Question

    The chance Andrea is most valuable player (MVP) is 0.4. THe chance that her friend is runner-up is 0.3. If the chance that Andrea is MVP and Brigid is runner-up s 0.2, what is chance that Andrea is MVP or Brigid is runner-up or both?

    I'm having trouble working out what we are after here.

    Thanks!
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by classicstrings View Post
    The chance Andrea is most valuable player (MVP) is 0.4. THe chance that her friend is runner-up is 0.3. If the chance that Andrea is MVP and Brigid is runner-up s 0.2, what is chance that Andrea is MVP or Brigid is runner-up or both?

    I'm having trouble working out what we are after here.

    Thanks!
    P(A)=0.4,
    P(B)=0.3
    P(A & B)=0.2

    find P(A v B).

    P(A v B) = P(A) + P(B) - P(A & B) = 0.5

    Draw a Venn diagram to see why this is so.

    RonL
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  3. #3
    Member classicstrings's Avatar
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    Yes, the answer is correct, however i still have trouble understanding,

    If P(A) = 0.4, this is the probability of Andrea getting MVP right?

    Then how is P(B) = 0.3, isn't this saying probability of Brigit getting MVP is 0.3, when it is not, and it is her getting "runner up" which is 0.3?

    What does A and B stand for here? I am confused... thanks.

    With a Venn diagram, there is a circle name A then a circle name B. In the intersection is 0.2, in just the A part 0.2, so Pr(A) = 0.4, and just in the B part it is 0.1, so P(B) = 0.3.
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