Two Mathematics books, three Chemistry books and four Physics books are to be arranged in a row on a shelf. Given that all the books are different, find the number of ways of arranging the books if no two Physics books are placed together.

the answer should be 43200.

I am able to find out the number of possible arrangement for the 4 physics books so that no two of them are placed together, which is 15.

so 15x4!x5!=43200.

But this method is a bit stupid since I need to count the possible arrangement one by one.

Is there a simpler way to solve it??? Please help!!