I would like to have some help with this problem about counting:
How many different three-letter initials with none of the letter repeated can people have?
I would say for the solution 23^3 since we have to remove 3 letter from the alphabet.
I am right?
Originally Posted by braddy
there 26 letters in the alphabet.
For the first initial you can choose one from the 26 letters.
For the second initial there are 25 left (one letter is used already)
For the third initial you have only 24 letters.
So the total amount of different 3-initials is: 26 * 25 * 24
Originally Posted by earboth