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Math Help - probability again..

  1. #1
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    probability again..

    A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the following events:

    One of the balls is yellow
    At least one ball is red
    Both balls are green
    Both balls are of the same color
    Find the following conditional probabilities: (a)
    (b)
    (c)
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  2. #2
    Member TheMasterMind's Avatar
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    Quote Originally Posted by asugirl87 View Post
    A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the following events:

    One of the balls is yellow
    At least one ball is red
    Both balls are green
    Both balls are of the same color
    Find the following conditional probabilities: (a)
    (b)
    (c)
    Well not being B/ gets rid of the both red case. So the only possibility for D/ that is not B/ is both are green. There are 3 out of 6 green balls for the first choice and then 2 out of 5 for the second,therefore the probability is (3/6) * (2/5) = 1/5.
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