# Math Help - probability again..

1. ## probability again..

A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the following events:

One of the balls is yellow
At least one ball is red
Both balls are green
Both balls are of the same color
Find the following conditional probabilities: (a)
(b)
(c)

2. Originally Posted by asugirl87
A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the following events:

One of the balls is yellow
At least one ball is red
Both balls are green
Both balls are of the same color
Find the following conditional probabilities: (a)
(b)
(c)
Well not being B/ gets rid of the both red case. So the only possibility for D/ that is not B/ is both are green. There are 3 out of 6 green balls for the first choice and then 2 out of 5 for the second,therefore the probability is (3/6) * (2/5) = 1/5.