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Math Help - Probability Problem

  1. #1
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    Probability Problem

    If one bag contains 4 white and 2 black balls; another contains 3 white and 5 black balls. If one ball is drawn from each bag
    find the probability that
    i) both are white
    ii) one is white and one is black.
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  2. #2
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    Re :

    Quote Originally Posted by zorro View Post
    if one bag contains 4 white and 2 black balls; another contains 3 white and 5 black balls. If one ball is drawn from each bag
    find the probability that
    i) both are white
    ii) one is white and one is black.

    (1) (4/6)(3/8)

    (2) (4/6)(5/8)+(2/6)(3/8)
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  3. #3
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    (1)
    Since 1 ball should be white from first bag (4W,2B;Total=6) and 1 ball should be white from second bag (3W,5B;Total=8)...

    Therefore ((4C1)/(6C1))*((3C1)/(8C1)) = 1/4

    (2)
    There are 2 cases...
    1.When First bag produce white and second bag produce black, then
    ((4C1)/(6C1))*((5C1)/(8C1)) = 5/12
    2.When First bag produce black and second bag produce white, then

    ((3C1)/(8C1))*((2C1)/(6C1)) = 1/8
    Add both the results and the answer is 13/24
    P.S. It can be wrong... I am a learner too...
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  4. #4
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    Quote Originally Posted by zorro View Post
    If one bag contains 4 white and 2 black balls; another contains 3 white and 5 black balls. If one ball is drawn from each bag
    find the probability that
    i) both are white
    ii) one is white and one is black.
    Drawing a tree diagram would be an excellent way of answering these questions ... (I suspect that's what mathaddict did).
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