If one bag contains 4 white and 2 black balls; another contains 3 white and 5 black balls. If one ball is drawn from each bag

find the probability that

i) both are white

ii) one is white and one is black.

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- Jan 6th 2009, 11:38 PMzorroProbability Problem
If one bag contains 4 white and 2 black balls; another contains 3 white and 5 black balls. If one ball is drawn from each bag

find the probability that

i) both are white

ii) one is white and one is black. - Jan 7th 2009, 02:40 AMmathaddictRe :
- Jan 7th 2009, 02:43 AMrshekhar.in
(1)

Since 1 ball should be white from first bag (4W,2B;Total=6) and 1 ball should be white from second bag (3W,5B;Total=8)...

Therefore ((4C1)/(6C1))*((3C1)/(8C1)) = 1/4

(2)

There are 2 cases...

1.When First bag produce white and second bag produce black, thenP.S. It can be wrong... I am a learner too...

((4C1)/(6C1))*((5C1)/(8C1)) = 5/122.When First bag produce black and second bag produce white, then

((3C1)/(8C1))*((2C1)/(6C1)) = 1/8Add both the results and the answer is 13/24

- Jan 7th 2009, 03:18 AMmr fantastic