# Probability Problem

• Jan 6th 2009, 11:38 PM
zorro
Probability Problem
If one bag contains 4 white and 2 black balls; another contains 3 white and 5 black balls. If one ball is drawn from each bag
find the probability that
i) both are white
ii) one is white and one is black.
• Jan 7th 2009, 02:40 AM
Re :
Quote:

Originally Posted by zorro
if one bag contains 4 white and 2 black balls; another contains 3 white and 5 black balls. If one ball is drawn from each bag
find the probability that
i) both are white
ii) one is white and one is black.

(1) (4/6)(3/8)

(2) (4/6)(5/8)+(2/6)(3/8)
• Jan 7th 2009, 02:43 AM
rshekhar.in
(1)
Since 1 ball should be white from first bag (4W,2B;Total=6) and 1 ball should be white from second bag (3W,5B;Total=8)...

Therefore ((4C1)/(6C1))*((3C1)/(8C1)) = 1/4

(2)
There are 2 cases...
1.When First bag produce white and second bag produce black, then
((4C1)/(6C1))*((5C1)/(8C1)) = 5/12
2.When First bag produce black and second bag produce white, then

((3C1)/(8C1))*((2C1)/(6C1)) = 1/8