Thanks for looking.
I appreciate your time and effort.
Ok so N = 8Suppose that 65% of the families in a town own computers. If eight families are surveyed at random, what is the prob. that at least four own computers ?
X = 4
Success = 0.65 ?
Failure = 0.35 ?
I am using the formulate :
I know i am doing something wrong...
The wording is really messing me up....Trump - airlines has dtermined 5% of its customers do not show up for their flights.
If a passenger is bumped off a flight because of overbooking, the airline pays the customer $200. What is the expected payout by the airline if it overbooks a 240 seat airplane by 5%
0.3In a binomial dist., if 10 trials are conducted, and the prb. of failure is 0.3, what is the expected value ?
N = 10
Q = 0.3
P = 0.7
Is that correct ?
Ok thanks for your time so far...
This is the hardest...
I am twisted in there...A manufacturer of electronics components produces precision resistors designd to have a tolerance of +/- 1%. from quality control testing, the manu. knows that about 1 resistor in 6 is actually within just 0.3% of its nominal value. A customer needs 5 of these more precise resistors. what is the prob. of finding exactly 5 such resistors aming the first 8 tested?
There are 2 of them....
1 in 6 and 5 in 8...