Let be the event of a family owning computers.

We are looking for . Note that

Since is , we now see that

Does this make sense?

I know i am doing something wrong...

The first bit is messing me up too...maybe mr fantastic or someone else can help you with this one.The wording is really messing me up....Trump - airlines has dtermined 5% of its customers do not show up for their flights.

If a passenger is bumped off a flight because of overbooking, the airline pays the customer $200. What is the expected payout by the airline if it overbooks a 240 sea airplane by 5%

Yes!N = 10In a binomial dist., if 10 trials are conducted, and the prb. of failure is 0.3, what is the expected value ?

0.3

3

0.7

7

None

Q = 0.3

P = 0.7

Is that correct ?

Let be the event of receive one of these nominal resistors. The probability of getting one nominal resistor is one out of six, or . The sample size/number of trials isOk thanks for your time so far...

This is the hardest...

I am twisted in there...A manufacturer of electronics components produces precision resistors designed to have a tolerance of +/- 1%. from quality control testing, the manu. knows that about 1 resistor in 6 is actually within just 0.3% of its nominal value. A customer needs 5 of these more precise resistors. what is the prob. of finding exactly 5 such resistors among the first 8 tested?

There are 2 of them....

1 in 6 and 5 in 8...

Thus, is . We can now see that

Does this make sense?