To answer your question directly, there are possibilities for the deal of 76 cards from the 104 card deck (disregarding the order of the cards). Of these, have exactly one Ten. So the probability of having exactly one Ten in the deal is .
However, I don't think that is really the question we should ask. There is nothing special about the rank Ten-- surely you would have been just as perplexed to have only one card of any given rank, and even worse, you could have zero cards of that rank. So I think a better question is this: What is the probability of dealing one or fewer cards of some rank?
If we draw zero cards of some rank, there are 13 ways to choose the rank and then to choose the remaining cards, so the total number of ways is , with probability .
If we draw exactly one card of some rank, there are 13 ways to choose the rank, 8 ways to choose the particular card, and then ways to choose the remaining cards, so the total number of ways is , with probability .
Finally, the probability of drawing zero or one cards of some rank is