Probability is not my forte so someone please correct me if I'm wrong.

1.

2.

3.

4.

5.

6.

These are all thedifferentpossibilities. Of these only one pair produces the required form, #2. So we need to pick two choices, of which there are only two elements we can choose. So by the counting principle we have 2 choices for the first factor, then we are left with only 1 possibility for the second choice. There are 4*3 ways to make a product of any two of the factors. So:

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So we have a 1 in 6 chance of getting the required product.

-Dan