I will have 7 numbers from 1 to 39. They can be any 7 numbers of 1 to 39. So how many parts i have to divide of those numbers. Example it can be 1,6,9,23,33,35,37 or other differents number. So can i have a solution of that?
Hello, faruk_fin!
I will assume the question is: In how may ways can we take 7 of 39 objects?I will have 7 numbers from 1 to 39. They can be any 7 numbers of 1 to 39.
So how many parts i have to divide of those numbers.
Example: it can be 1,6,9,23,33,35,37 or other differents number.
So can i have a solution of that?
The answer is: .$\displaystyle _{39}C_7 \;=\;{39\choose7} \;=\;\frac{39!}{7!\,32!} \;=\;15,\!380,\!937 $ ways.
Thanks a lot.
But i want to know how many times i have to write those numbers 1 t0 39 n each time their will be 7 numbers. So if someone give me any 7 numbers of 1 to 39 at least their will be similarity once. Plz help me. Thanks again.
Thanks a lot.
But i want to know how many times i have to write those numbers 1 t0 39 n each time their will be 7 numbers. So if someone give me any 7 numbers of 1 to 39 at least their will be similarity once. And how have to write all those numbers different time? Plz help me. Thanks again.
It not that kind. I want know how many times i have to write those numbers n how many parts they will be. Each time ther will be 7 numbers they must to be 1 to 39. So any 7 numbers i get there will be similarity. Plz help.
Hello again, faruk_fin!
I'll take a guess at what you are asking . . .
We have a list of the 15,380,937 sets of seven numbers from the set 1-to-39.
. . $\displaystyle \begin{array}{c} \{1,2,3,4,5,6,7\} \\ \{1,2,3,4,5,6,8\} \\ \{1,2,3,4,5,6,9\} \\ \vdots \\ \{33,34,35,36,37,38,39\} \end{array}$
How many times does a particular number (say, 23) appear on the list?
I would conjecture that any number appears $\displaystyle \tfrac{1}{39}$ of the time.
Therefore, "23" appears $\displaystyle \frac{15,380,937}{39} \:=\:394,383$ times.