I will have 7 numbers from 1 to 39. They can be any 7 numbers of 1 to 39. So how many parts i have to divide of those numbers. Example it can be 1,6,9,23,33,35,37 or other differents number. So can i have a solution of that?(Surprised)

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- Dec 22nd 2008, 12:41 PMfaruk_finsolution combinations
I will have 7 numbers from 1 to 39. They can be any 7 numbers of 1 to 39. So how many parts i have to divide of those numbers. Example it can be 1,6,9,23,33,35,37 or other differents number. So can i have a solution of that?(Surprised)

- Dec 22nd 2008, 12:46 PMPlato
Are you asking: "How subsets of seven numbers are there using the integers 1 to 39?"

- Dec 22nd 2008, 12:57 PMSoroban
Hello, faruk_fin!

Quote:

I will have 7 numbers from 1 to 39. They can be any 7 numbers of 1 to 39.

So how many parts i have to divide of those numbers.

Example: it can be 1,6,9,23,33,35,37 or other differents number.

So can i have a solution of that?

The answer is: .$\displaystyle _{39}C_7 \;=\;{39\choose7} \;=\;\frac{39!}{7!\,32!} \;=\;15,\!380,\!937 $ ways.

- Dec 23rd 2008, 11:22 AMfaruk_fin
Thanks a lot.

But i want to know how many times i have to write those numbers 1 t0 39 n each time their will be 7 numbers. So if someone give me any 7 numbers of 1 to 39 at least their will be similarity once. Plz help me. Thanks again.(Worried)

Thanks a lot.

But i want to know how many times i have to write those numbers 1 t0 39 n each time their will be 7 numbers. So if someone give me any 7 numbers of 1 to 39 at least their will be similarity once. And how have to write all those numbers different time? Plz help me. Thanks again.(Worried)

It not that kind. I want know how many times i have to write those numbers n how many parts they will be. Each time ther will be 7 numbers they must to be 1 to 39. So any 7 numbers i get there will be similarity. Plz help. - Dec 23rd 2008, 04:05 PMPlato
- Dec 24th 2008, 11:46 AMSoroban
Hello again, faruk_fin!

I'll take a guess at what you are asking . . .

We have a list of the 15,380,937 sets of seven numbers from the set 1-to-39.

. . $\displaystyle \begin{array}{c} \{1,2,3,4,5,6,7\} \\ \{1,2,3,4,5,6,8\} \\ \{1,2,3,4,5,6,9\} \\ \vdots \\ \{33,34,35,36,37,38,39\} \end{array}$

How many times does a particular number (say, 23) appear on the list?

I would conjecture thatnumber appears $\displaystyle \tfrac{1}{39}$ of the time.*any*

Therefore, "23" appears $\displaystyle \frac{15,380,937}{39} \:=\:394,383$ times.