If a fair dice is tossed 10 times - what is the probability of at least 2 6's?
What is the general 'formula', say I want at least 4 6's etc..
Thanks
Let X be the random variable number of 6's.
X ~ Binomial(n = 10, p = 1/6).
Calculate $\displaystyle \Pr(X \geq 2) = 1 - \Pr(X \leq 1) = 1 - \Pr(X = 0) - \Pr(X = 1)$.
Use the formula given here: Binomial Distribution (1 of 3)