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Math Help - Probability - fair dice - at least 2 6's in 10 tosses

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    Probability - fair dice - at least 2 6's in 10 tosses

    If a fair dice is tossed 10 times - what is the probability of at least 2 6's?

    What is the general 'formula', say I want at least 4 6's etc..

    Thanks
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    Quote Originally Posted by lorenz View Post
    If a fair dice is tossed 10 times - what is the probability of at least 2 6's?

    What is the general 'formula', say I want at least 4 6's etc..

    Thanks
    Let X be the random variable number of 6's.

    X ~ Binomial(n = 10, p = 1/6).

    Calculate \Pr(X \geq 2) = 1 - \Pr(X \leq 1) = 1 - \Pr(X = 0) - \Pr(X = 1).

    Use the formula given here: Binomial Distribution (1 of 3)
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    Thank you very much
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