5 balls are picked at random one at a time and then replaced. If 65% of balls are blue, 30% are red and 5% are green. Then what is the probability that

i) All 5 balls are red

ii) 3 are blue, 1 is green and 1 is red

iii) At least 1 is a green

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- December 16th 2008, 09:36 AMfeage7Probability Question
5 balls are picked at random one at a time and then replaced. If 65% of balls are blue, 30% are red and 5% are green. Then what is the probability that

i) All 5 balls are red

ii) 3 are blue, 1 is green and 1 is red

iii) At least 1 is a green - December 16th 2008, 09:40 AMcolby2152
- December 16th 2008, 06:14 PMmr fantastic
To the OP: Read Multinomial distribution - Wikipedia, the free encyclopedia

- December 19th 2008, 10:18 PMxzed
Mr. F, I don't understand why you multiplied it by 20?

because if you pick, that's a combination, so the arrangement shouldn't matter, I might be wrong, since I am new to probability - December 20th 2008, 03:15 AMPim
The reason it has to be multiplied is exactly because order does not matter.

Assumes that you first pick three blue balls, then a green one, then a red one. Because order does not matter, you'll need to multiply this by the amount of combinations possible, which in this case is: