find the probability that 7 out of 10 persons will recover from a tropical disease; if the probability that any one will recover from the disease is 0.80.
Hello
It is ( aka binomial distribution)
$\displaystyle \begin{pmatrix} 10 \\ 7 \end{pmatrix} 0.8^7 * 0.2^3$
$\displaystyle = \frac{10!}{(10-7)! * 7!} * 0.8^7 * 0.2^3$
$\displaystyle = \frac{10*9*8}{3!} * 0.8^7 * 0.2^3 \approx 20.13\% $
Rapha