# Thread: probability

1. ## probability

find the probability that 7 out of 10 persons will recover from a tropical disease; if the probability that any one will recover from the disease is 0.80.

2. Hello

It is ( aka binomial distribution)

$\begin{pmatrix} 10 \\ 7 \end{pmatrix} 0.8^7 * 0.2^3$

$= \frac{10!}{(10-7)! * 7!} * 0.8^7 * 0.2^3$

$= \frac{10*9*8}{3!} * 0.8^7 * 0.2^3 \approx 20.13\%$

Rapha