find the probability that 7 out of 10 persons will recover from a tropical disease; if the probability that any one will recover from the disease is 0.80.

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- Dec 9th 2008, 04:14 AMZandraprobability
find the probability that 7 out of 10 persons will recover from a tropical disease; if the probability that any one will recover from the disease is 0.80.

- Dec 9th 2008, 05:21 AMRapha
Hello

It is ( aka binomial distribution)

$\displaystyle \begin{pmatrix} 10 \\ 7 \end{pmatrix} 0.8^7 * 0.2^3$

$\displaystyle = \frac{10!}{(10-7)! * 7!} * 0.8^7 * 0.2^3$

$\displaystyle = \frac{10*9*8}{3!} * 0.8^7 * 0.2^3 \approx 20.13\% $

Rapha