In a class of 33 boys and 8 girls what is the probability of the first and second child to arrive in the morning to be a boy?
Thanks in advance to anybody who answers
Hey, thanks for taking the time to reply.
I am not big on Maths, and am doing this as a small part of my Sociology course (Statistics), but the answer you gave is exactly the same answer that I gave, 33/41. I thought it might be wrong when I wrote it but wanted to write something rather than nothing.
It is marked wrong. So are we sure that is the right answer?
If you draw a tree diagram it should be clear that the answer is $\displaystyle \left(\frac{33}{41}\right) \cdot \left(\frac{32}{40}\right)$.
This answer will only be correct if the first child goes back home because s/he forgot his/her lunch .....
(In other words, sampling with replacement)