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Math Help - Card Probability

  1. #1
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    Card Probability

    I have some problems similar to this, but in the back of the book it just says answers will vary...

    Could someone please break this down to me?

    Given events A and B within the sample space S, the following sequence of steps establishes formulas that can be used to compute conditional probabilities. Justify each statement.

    a) P(A and B) = P(A) * P(B|A)

    b)Therefore, P(B|A) = P(A and B)/P(A)

    c) Therefore, P(B|A) = n(A and B)/n(S) over n(A)/n(S)

    d)Therefore, P(B|A) = n(A and B)/ n(A)

    Use the results from above to find each probability in a standard deck of 52 cards.

    Like this one for example:

    P (red | diamond)
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  2. #2
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    Anyone, Blam da Blam...

    I was wondering if it all meant the same thing...


    I would think it is saying red intersects diamond/ red, but this just doesn't seem right to me.
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  3. #3
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    Quote Originally Posted by WhoaBlackBetty View Post
    I have some problems similar to this, but in the back of the book it just says answers will vary...

    Could someone please break this down to me?

    Given events A and B within the sample space S, the following sequence of steps establishes formulas that can be used to compute conditional probabilities. Justify each statement.

    a) P(A and B) = P(A) * P(B|A)

    b)Therefore, P(B|A) = P(A and B)/P(A)

    c) Therefore, P(B|A) = n(A and B)/n(S) over n(A)/n(S)

    d)Therefore, P(B|A) = n(A and B)/ n(A)

    Use the results from above to find each probability in a standard deck of 52 cards.

    Like this one for example:

    P (red | diamond) Mr F says: This probability is obviously equal to 1.
    ..
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  4. #4
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    Ok...thank you. Its kind of what I thought. I will just go through the other ones. I thought maybe this was some kind of trick question.
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