Thread: Z problem

I calculated my z value to be z=(23-18)/3 = 5/3 = 1.66

I am trying to find P(Z>1.6666) = ?

can someone please explain how to get this probability using the Z table?

thanks in advance

i got 0.0485

0.5 - 0.4515

Hello,

Originally Posted by ndcruz

I calculated my z value to be z=(23-18)/3 = 5/3 = 1.66

I am trying to find P(Z>1.6666) = ?

can someone please explain how to get this probability using the Z table?

thanks in advance

i got 0.0485

0.5 - 0.4515

Well, if this is what you got by using the Z table, then you know how to use it, because your answer is correct...

The z table represents the area bounded by the Gaussian curve, the x axis, the y axis and the line x=a, where a is the z value of the table.

So in fact, tables give you this probability :

Let a>0 and b<0. Let and be the z scores of a and b.