Sorry, forgot about this one. I would suggest using X as the number of wins and Y as the number of losses. Then X has a binomial distribution with parameters (30,2/6) and Y has a binomial distribution with parameters (30-X,3/4). From this you can determine the joint pmf and then figure out how likely it is that Y>X.
2.Randomly select a number from the box with numbers -2,-2,-2, 0, 2, 2 and the number obtained is the amount of dollars you get. Play the game 30 times, use normal approximation to find the chance that you will be in the , losing some money.