two parts

for F(y) = 2(sigma-y)/sigma^2 sigma > y > 0

0 elsewhere

show that y/sigma is a pivotal quantity

use the pivotal quantity to construct a 80% confidence interval for sigma

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- November 24th 2008, 11:49 AMbatemanlpivotal quantities
two parts

for F(y) = 2(sigma-y)/sigma^2 sigma > y > 0

0 elsewhere

show that y/sigma is a pivotal quantity

use the pivotal quantity to construct a 80% confidence interval for sigma - November 24th 2008, 05:48 PMmr fantastic
Have you tried reading these threads:

http://www.mathhelpforum.com/math-he...tribution.html

http://www.mathhelpforum.com/math-he...-function.html

http://www.mathhelpforum.com/math-he...-interval.html

http://www.mathhelpforum.com/math-he...-interval.html

If this doesn't help, I'll try to find the time later to say something specific about your question. - November 24th 2008, 07:52 PMmr fantastic
Let .

Using the transformation method to get the pdf of U:

.

.

Note: The above gives the pdf for U when 0 < u < 1 (why?). Otherwise .

So the two conditions for U to be a pivotal quantity are met.

You can also easily get the pdf of U by first getting the cdf of U and then using .

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Now you require two numbers and such that .

So solve and using the pdf for U found above. Then:

.

Now you need data .....