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Math Help - Combinations Question - Help

  1. #1
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    Combinations Question - Help

    23. From a group of 6 women and 4 men, determine in how many ways a committee of 4 people can be selected with

    a) no restriction
    my answer:

    C (10,4) = 10! 6! 4! = 210 ways

    b) 4 women

    c) 3 women and 1 man

    d) 2 women and 2 men

    e) 4 men

    .. if someone could do b and c for me... I will figure out how to do the rest on my own.
    Thanks!
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  2. #2
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    b) {6 \choose 4}

    c) {6 \choose 3}{4 \choose 1}
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  3. #3
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    Therefore.. the answer to D) will be ( 6 2) ( 4 2)


    and the answer to e will be.... (6 0) (4 4) -- for an answer of one? Or is this a special case since all of the men are being used for the selection. The answer of just 1 does not seem correct to me. I was thinking more along the lines of 4! for an answer of 24?
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