[SOLVED] 2-sided confidence interval for small sample
33. degrees of polymerization are:
418 421 421 422 425 427 431
434 437 439 446 447 448 453
454 463 465
c. Calculate a two-sided 95% confidence interval for true average degree of polymerization.
n=17 (so I will calculate a t-confidence interval)
t-confidence interval= mean +/- (t-critical value * s/√n)
I have calculated ∑x=7,451 so ∑x²=55,517,401. So the mean is 7,451/17≈ 438.29. t-critical value is 2.11. √n=√17≈4.123.
If I understand this, then I just need to calculate s to attain the confidence interval. However, I don't know how to calculate s without having the probability of each x. (i.e. √σ=E(x²)-[E(x)]²).
Please let me know how my logic is failing and what I need to do to solve this problem. I have spend several hours on this.
Thanks a bunch!
formula for sample standard deviation
I found my answer:
Hope this helps others.