Results 1 to 4 of 4

Math Help - probability

  1. #1
    Junior Member
    Joined
    Oct 2008
    Posts
    57

    probability

    4. Seven cards each containing one of the following letters C,B,T,A,E,M and H are placed in a hat. Each letter is used only once. Stu will pull four cards out at random and without replacement. what is the probability that Stu pulls out M,A,T,H in order?? express your answer as a common fraction.



    5. If x and y are positive integers with x+y<40, what is the largest possible product xy?



    6. Consider the rectangular region with vertices at (5,4), (-5,4), (-5,-4) and (5,-4). how many points with integer coordinates will be strictly in the interior of this rectangular region?


    7. What is the degree measure of an interior angle of a regular pentagon?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Nov 2008
    From
    rochester, ny
    Posts
    8

    polygon angles

    You can figure out the value of any interior angle of a polygon by letting
    n= the number of sides

    180(n-2)/n

    For a pentagon

    180(5-2)/5
    =108 degrees
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2008
    From
    rochester, ny
    Posts
    8
    If x+y are 2 integers less than 40 but not equal to. Then their sum must be 39. If you take the 2 largest integers whose sum is 39, ie 19 and 20, their product will be 380. That should be your answer.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Nov 2008
    From
    rochester, ny
    Posts
    8
    4. Seven cards each containing one of the following letters C,B,T,A,E,M and H are placed in a hat. Each letter is used only once. Stu will pull four cards out at random and without replacement. what is the probability that Stu pulls out M,A,T,H in order?? express your answer as a common fraction.

    M,A,T,H should have the same probability as pulling out any other four letter combination with out replacement.
    Therefore you have
    (1/7) chance of pulling M
    (1/6) chance of pulling A next
    (1/5) chance for T next
    (1/4) chance to pull H last

    1/(7*6*5*4)= 1/840 chance of pulling M,A,T,H or any other specific four card combination without replacement
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 10
    Last Post: January 21st 2011, 12:47 PM
  2. Replies: 3
    Last Post: May 29th 2010, 08:29 AM
  3. fundamental in probability & convergence with probability 1
    Posted in the Advanced Statistics Forum
    Replies: 3
    Last Post: February 23rd 2010, 10:58 AM
  4. Replies: 1
    Last Post: February 18th 2010, 02:54 AM
  5. Replies: 3
    Last Post: December 15th 2009, 07:30 AM

Search Tags


/mathhelpforum @mathhelpforum