The propability is not my strength but, I remember that we have 1/36 to have 2 and 1/36 to have 12 as overall outcome.
so for not 2 could be
and for 6
=> think to 2 you have 1/6 for the first dice and 1/6 for the second so 1/36
Hope that it is useful (Sleepy)
It's just matter of counting, isn't it?
There are 36 possible outcomes.
There are: . ways to get a sum of 2, 4 or 6.
So there are: . ways for some other sum.