The sides of a fair six-sided dice are numbered from 1 to 6 The dice is thrown three times Find the probabilitty that it shows a 1 at least twice.
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Originally Posted by abey_27 The sides of a fair six-sided dice are numbered from 1 to 6 The dice is thrown three times Find the probabilitty that it shows a 1 at least twice. This is a binomial distribution. $\displaystyle P(X \geq 2) = \sum_{n = 2}^{3} {3 \choose n} \left( \frac{1}{6} \right) ^{n} \left( \frac{1}{6} \right) ^{3 - n} $
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