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**HallsofIvy** Assuming each of the areas on each spinner are of equal size (you didn't say that), all the outcomes are equally likely. The first spinner has 4 equally likely areas so the probability of any one of them is 1/4. The second spinner has 3 equally likely areas so the probability of any one of them is 1/3. The third spinner has two equally likely areas so the probability of any one of them is 1/2.

If A and B are "mutually exclusive" (as are different areas on each spinner- the needle cannot point to two different areas) then the probability of "A or B" is the probability of A plus the probability of B.

If A and B are "independent" (as are the results of different spinners- the result of one spin does not affect the spin of another) then the probability of "A and B" is the product of the probability of A and the probability of B.

The probability of "forward" is 1/2 and the probability of "yellow or green" is 1/3+ 1/3= 2/3. The probability of getting "forward" and "yellow or green" is (1/2)(2/3)= 1/3.

The probability of getting "yellow" is 1/3, the probability of getting "2 or 4" is 1/4+ 1/4= 1/2, and the probability of getting "backward" is 1/2. The probability of getting "yellow" and "2 or 4" and "backward" is (1/3)(1/2)(1/2)= 1/12.