A committee of four members is selected randomly from a list of ten names.
The list has the names of five union members and five non-union workers.
a) What is the probability that the first person selected is a union member? 1/2
b) What is the probability that the first 2 people selected are union members? 5/10 x 4/9 = 2/9
c) What is the probability that all commitee members are union members? 1/42
All correct . . . good work!There are many ways to approach this one. .Here's one way . . .d) What is the probability that three of the four committee members are union members?
There are: . posslble committees.
We want 3 Union workers.
There are: . ways to choose them.
We want 1 non-union worker.
There are: . ways to choose him.
Hence, there are: . ways to have exactly 3 union members.