There are 3 total red jokers and red aces in the deck of 54 cards. If you mean the probability of drwaing at least 1 of them then you look at the 3 possible cases. Draw a red on first but not second, draw a red on second but not first, and draw a red on both.

Draw a red on first but not second = (3/54)(51/53)

Draw a red on second but not first = (51/54)(3/53)

Draw a red on both = (3/54)(2/53)'

Then you add them all up = (153+153+6)/(54)(53) = 312/2862 = 52/477, or about .109.