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Math Help - More probability problems.

  1. #1
    Junior Member
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    More probability problems.

    Two Dice are rolled: one is red and the other is white.
    a) How many outcomes are possible? 6x6(each dice)=36

    b) Determine the probability that the sum of the two dice totals anything but seven? I don't know how to approach this one I cant get the answer which is 5/6.

    c) Determine the probability that the sum of the two dices totals seven? same thing but the answer is 1/6.
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  2. #2
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    your solution to A) is correct.

    for B) you can get a 7 by with these values (1,6), (2,5), (3,4), (5,2), (6,1). now each of these outcomes has probability \frac{1}{36}, therefore summing them up we get \frac{6}{36} = \frac{1}{6}. Now since we want the probability that it's not a 7, which is 1-P(X=7) = 1-\frac{1}{6} = \frac{5}{6}

    for C) it's just the former part of the explanation of B).
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