# who can answer any of these

• Oct 7th 2008, 07:18 PM
sf415415
who can answer any of these
find each of the following probabilities for a normal distribution:
a. p(z>-1.00)
b. p(z>-0.80)
c. p(z<0.25)
d. p(z<1.25)

for a normal distribution idenitfy the z-score location that would seperate the distriubtion into two sections so there is:
a. 70% in the body on the right-hand side.
b. 80% in the body on the right-hand side.
c. 75% in the body on the left-hand side.
d. 90% in the body on the left-hand side.

information from the dmv induicates the average of licensed drivers is mean- 39.7 and standard deviation of o- 12.5 years. assume that the distriubtion of drivers age is approx. normal.

a. x=85
b.x= 92
c. x=78
d. x=72
• Oct 7th 2008, 07:57 PM
CaptainBlack
Quote:

Originally Posted by sf415415
find each of the following probabilities for a normal distribution:
a. p(z>-1.00)
b. p(z>-0.80)
c. p(z<0.25)
d. p(z<1.25)

for a normal distribution idenitfy the z-score location that would seperate the distriubtion into two sections so there is:
a. 70% in the body on the right-hand side.
b. 80% in the body on the right-hand side.
c. 75% in the body on the left-hand side.
d. 90% in the body on the left-hand side.

information from the dmv induicates the average of licensed drivers is mean- 39.7 and standard deviation of o- 12.5 years. assume that the distriubtion of drivers age is approx. normal.

a. x=85
b.x= 92
c. x=78
d. x=72

Using the fact that for the standard normal distribution:

$F(-x)=1-F(x)$

and for an arbitary normal distrbution that:

$z=\frac{x-\mu}{\sigma}$

has a standard normal distribution, you will find the answers to all your problems here.

(and the last question as it is makes no sense)

RonL