Hello, I thought this would of been easy but I am second guessing myself.
Frank, Tom, Jim and 6 other boys are randomly seated in a row. What
is the probability that neither Frank nor Tom sits next to Jim?
Here is what I came up with. However, I am not confident in it, because it seems rather low.
(6! x 9)/(9!) = 0.0178... or 1.78%